I’m going to diverge a bit from our RedState Echo Chamber® and come out in support of the Occupy Wall Street protests. I’m struggling to find a downside to this bit of theater for conservatives or the GOP. I don’t really see an upside to it for the Administration and the Democrats.

Personally, I can’t think of anything more amusing than several heavily blue cities being overrun by unwashed hipster trash protesting the excesses… or existence… of the industry group that has given Obama truckloads of money. If heads are broken, it will be under the direction of Democrat mayors. If people are inconvenienced they are by and large Democrat voters.

The media will eat it up as they vicariously relive their recollections of what Woodstock would have been like if only they had been conceived or out of diapers at the time. Night after night the nation will be reminded of exactly who is in the White House.

The administration fantasizes that it will create some sort of counter Tea Party but misses the obvious disconnect. The Tea Party was for something rather than merely an inchoate protest for the sake of protest. More to the point, where the Tea Party found a natural, if somewhat strained, alliance with the GOP, it is hard to see how these protesters find alliance with the political party that came to, and remains in, power by monetary contributions from Wall Street.

What they forget is that the street demonstrations of the mid-1960s did not help the Democrat party. To the contrary the protests of 1967 and 1968 led directly to the decision of LBJ to decline to seek a second term and to the election of Richard Nixon.

I think the conservatives should get behind this movement. We should make sure these people are able to stay in downtown Boston and New York City and Atlanta and wherever. We should send aid convoys from Red States to the #OWS protests to show that we, too, have been victimized by Barack Obama’s donor base. And we should make sure they get free bus tickets to the Democrat Convention in Charlotte, North Carolina.